Given a list of numbers, reorder it in zigzag
order.
Let's say the given list of numbers is numbers
. Zigzag
order of numbers
should follow the following order:
numbers[0] <= numbers[1] >= numbers[2] <= numbers[3]...
.
{
"numbers": [3, 5, 6, 1, 4, 2]
}
Output:
[3, 6, 1, 5, 2, 4]
Explanation: [2, 5, 3, 4, 1, 6]
is also accepted.
{
"numbers": [3, 1, 3, 1, 2, 4]
}
Output:
[1, 3, 1, 3, 2, 4]
Constraints:
/*
Asymptotic complexity in terms of number of elements \`n\`:
* Time: O(n).
* Auxiliary space: O(1).
* Total space: O(n).
*/
vector<int> zigzag_sort(vector<int> &numbers) {
for (int i = 0; i + 1 < (int)numbers.size(); i++) {
if (i % 2 == 0 && numbers[i] > numbers[i + 1]) {
swap(numbers[i], numbers[i + 1]);
}
else if (i % 2 == 1 && numbers[i] < numbers[i + 1]) {
swap(numbers[i], numbers[i + 1]);
}
}
return numbers;
}
We hope that these solutions to zigzag sort problem have helped you level up your coding skills. You can expect problems like these at top tech companies like Amazon and Google.
If you are preparing for a tech interview at FAANG or any other Tier-1 tech company, register for Interview Kickstart's FREE webinar to understand the best way to prepare.
Interview Kickstart offers interview preparation courses taught by FAANG+ tech leads and seasoned hiring managers. Our programs include a comprehensive curriculum, unmatched teaching methods, and career coaching to help you nail your next tech interview.
We offer 18 interview preparation courses, each tailored to a specific engineering domain or role, including the most in-demand and highest-paying domains and roles, such as:
To learn more, register for the FREE webinar.
Given a list of numbers, reorder it in zigzag
order.
Let's say the given list of numbers is numbers
. Zigzag
order of numbers
should follow the following order:
numbers[0] <= numbers[1] >= numbers[2] <= numbers[3]...
.
{
"numbers": [3, 5, 6, 1, 4, 2]
}
Output:
[3, 6, 1, 5, 2, 4]
Explanation: [2, 5, 3, 4, 1, 6]
is also accepted.
{
"numbers": [3, 1, 3, 1, 2, 4]
}
Output:
[1, 3, 1, 3, 2, 4]
Constraints:
/*
Asymptotic complexity in terms of number of elements \`n\`:
* Time: O(n).
* Auxiliary space: O(1).
* Total space: O(n).
*/
vector<int> zigzag_sort(vector<int> &numbers) {
for (int i = 0; i + 1 < (int)numbers.size(); i++) {
if (i % 2 == 0 && numbers[i] > numbers[i + 1]) {
swap(numbers[i], numbers[i + 1]);
}
else if (i % 2 == 1 && numbers[i] < numbers[i + 1]) {
swap(numbers[i], numbers[i + 1]);
}
}
return numbers;
}
We hope that these solutions to zigzag sort problem have helped you level up your coding skills. You can expect problems like these at top tech companies like Amazon and Google.
If you are preparing for a tech interview at FAANG or any other Tier-1 tech company, register for Interview Kickstart's FREE webinar to understand the best way to prepare.
Interview Kickstart offers interview preparation courses taught by FAANG+ tech leads and seasoned hiring managers. Our programs include a comprehensive curriculum, unmatched teaching methods, and career coaching to help you nail your next tech interview.
We offer 18 interview preparation courses, each tailored to a specific engineering domain or role, including the most in-demand and highest-paying domains and roles, such as:
To learn more, register for the FREE webinar.
Attend our free webinar to amp up your career and get the salary you deserve.